C++编程：定义一个结构体变量（包括年、月、日），编写程序，要求输入年月日，程序能够计算并输出改日是本年中的第几天。注意闰年问题。
 
 以下是此题的【c++源代码】，需要【c源代码】请点击进入
 
源代码1：
#include <iostream>
using namespace std;
struct
   { int year;
     int month;
     int day;
   }date;
int main()
 {int days;
  cout<<"input year,month,day:";
  cin>>date.year>>date.month>>date.day;
  switch(date.month)
  { case 1: days=date.day;      break;
    case 2: days=date.day+31;   break;
    case 3: days=date.day+59;   break;
    case 4: days=date.day+90;   break;
    case 5: days=date.day+120;  break;
    case 6: days=date.day+151;  break;
    case 7: days=date.day+181;  break;
    case 8: days=date.day+212;  break;
    case 9: days=date.day+243;  break;
    case 10: days=date.day+273; break;
    case 11: days=date.day+304; break;
    case 12: days=date.day+334; break;
 }
 if ((date.year %4== 0 && date.year % 100 != 0
      ||date.year % 400 == 0) && date.month >=3)
         days+=1;
 cout<<date.month<<"/"<<date.day<<" is the "<<days
  <<"th day in "<<date.year<<"."<<endl;
 return 0;
}

源代码2
#include <iostream>
using namespace std;
struct
     {int year;
     int month;
     int day;
  }date;
 int main()
    {int i,days;
     int day_tab[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
     cout<<"input year,month,day:";
     cin>>date.year>>date.month>>date.day;
     days=0;
     for (i=1;i<date.month;i++)
       days+=day_tab[i];
     days+=date.day;
     if ((date.year%4==0 && date.year%100!=0 || date.year%400==0) && date.month>=3)
       days+=1;
     cout<<date.month<<"/"<<date.day<<" is the "<<days
    <<"th day in "<<date.year<<"."<<endl;
    return 0;
}

来源：c++程序设计第三版谭浩强课后答案

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